111300002111 has 2 divisors, whose sum is σ = 111300002112. Its totient is φ = 111300002110.

The previous prime is 111300002089. The next prime is 111300002113. The reversal of 111300002111 is 111200003111.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 111300002111 - 2³⁴ = 94120132927 is a prime.

Together with 111300002113, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 111300002092 and 111300002101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111300002113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55650001055 + 55650001056.

It is an arithmetic number, because the mean of its divisors is an integer number (55650001056).

Almost surely, 2^111300002111 is an apocalyptic number.

111300002111 is a deficient number, since it is larger than the sum of its proper divisors (1).

111300002111 is an equidigital number, since it uses as much as digits as its factorization.

111300002111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 111300002111 its reverse (111200003111), we get a palindrome (222500005222).

The spelling of 111300002111 in words is "one hundred eleven billion, three hundred million, two thousand, one hundred eleven".