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111312100020983 is a prime number
BaseRepresentation
bin11001010011110011011110…
…001011100101001011110111
3112121010022222122012222200112
4121103303132023211023313
5104042214140101132413
61032424023420533235
732306014414625321
oct3123633613451367
9477108878188615
10111312100020983
113251621861a224
12105990450b121b
134a158bc180614
141d6b76a502611
15cd073aa642a8
hex653cde2e52f7

111312100020983 has 2 divisors, whose sum is σ = 111312100020984. Its totient is φ = 111312100020982.

The previous prime is 111312100020967. The next prime is 111312100021027. The reversal of 111312100020983 is 389020001213111.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 111312100020983 - 24 = 111312100020967 is a prime.

It is a super-2 number, since 2×1113121000209832 (a number of 29 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111312100020383) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55656050010491 + 55656050010492.

It is an arithmetic number, because the mean of its divisors is an integer number (55656050010492).

Almost surely, 2111312100020983 is an apocalyptic number.

111312100020983 is a deficient number, since it is larger than the sum of its proper divisors (1).

111312100020983 is an equidigital number, since it uses as much as digits as its factorization.

111312100020983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 32.

The spelling of 111312100020983 in words is "one hundred eleven trillion, three hundred twelve billion, one hundred million, twenty thousand, nine hundred eighty-three".