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11132301119 is a prime number
BaseRepresentation
bin10100101111000100…
…10110111100111111
31001201211101111020212
422113202112330333
5140244332113434
65040351503035
7542603666252
oct122742267477
931654344225
1011132301119
1147a2991665
1221a8227a7b
13108546a634
147786ad099
154524c48ce
hex297896f3f

11132301119 has 2 divisors, whose sum is σ = 11132301120. Its totient is φ = 11132301118.

The previous prime is 11132301113. The next prime is 11132301121. The reversal of 11132301119 is 91110323111.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11132301119 - 212 = 11132297023 is a prime.

It is a super-2 number, since 2×111323011192 (a number of 21 digits) contains 22 as substring.

Together with 11132301121, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11132301094 and 11132301103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11132301113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566150559 + 5566150560.

It is an arithmetic number, because the mean of its divisors is an integer number (5566150560).

Almost surely, 211132301119 is an apocalyptic number.

11132301119 is a deficient number, since it is larger than the sum of its proper divisors (1).

11132301119 is an equidigital number, since it uses as much as digits as its factorization.

11132301119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 23.

The spelling of 11132301119 in words is "eleven billion, one hundred thirty-two million, three hundred one thousand, one hundred nineteen".