Base | Representation |
---|---|
bin | 10000001100110110011… |
… | …101100101000110111100 |
3 | 10221102122111122200222121 |
4 | 100030312131211012330 |
5 | 121220024411103000 |
6 | 2211240410252324 |
7 | 143301603005224 |
oct | 20146635450674 |
9 | 3842574580877 |
10 | 1113310253500 |
11 | 39a1746834a5 |
12 | 15b9254270a4 |
13 | 80ca5527b13 |
14 | 3bc55115084 |
15 | 1de5e289b1a |
hex | 103367651bc |
1113310253500 has 48 divisors (see below), whose sum is σ = 2559441699360. Its totient is φ = 421885987200.
The previous prime is 1113310253453. The next prime is 1113310253509. The reversal of 1113310253500 is 53520133111.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1113310253509) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 58585777 + ... + 58604776.
It is an arithmetic number, because the mean of its divisors is an integer number (53321702070).
Almost surely, 21113310253500 is an apocalyptic number.
1113310253500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1113310253500 is an abundant number, since it is smaller than the sum of its proper divisors (1446131445860).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1113310253500 is a wasteful number, since it uses less digits than its factorization.
1113310253500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 117190591 (or 117190579 counting only the distinct ones).
The product of its (nonzero) digits is 1350, while the sum is 25.
Adding to 1113310253500 its reverse (53520133111), we get a palindrome (1166830386611).
The spelling of 1113310253500 in words is "one trillion, one hundred thirteen billion, three hundred ten million, two hundred fifty-three thousand, five hundred".
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