1114055233 has 2 divisors, whose sum is σ = 1114055234. Its totient is φ = 1114055232.

The previous prime is 1114055231. The next prime is 1114055273. The reversal of 1114055233 is 3325504111.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1099055104 + 15000129 = 33152^2 + 3873^2 .

It is an emirp because it is prime and its reverse (3325504111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1114055233 - 2¹ = 1114055231 is a prime.

It is a super-2 number, since 2×1114055233² = 2482238124349368578, which contains 22 as substring.

Together with 1114055231, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1114055198 and 1114055207.

It is not a weakly prime, because it can be changed into another prime (1114055231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557027616 + 557027617.

It is an arithmetic number, because the mean of its divisors is an integer number (557027617).

Almost surely, 2^1114055233 is an apocalyptic number.

It is an amenable number.

1114055233 is a deficient number, since it is larger than the sum of its proper divisors (1).

1114055233 is an equidigital number, since it uses as much as digits as its factorization.

1114055233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1800, while the sum is 25.

The square root of 1114055233 is about 33377.4659463537. The cubic root of 1114055233 is about 1036.6581689710.

Adding to 1114055233 its reverse (3325504111), we get a palindrome (4439559344).

The spelling of 1114055233 in words is "one billion, one hundred fourteen million, fifty-five thousand, two hundred thirty-three".