11141211042133 has 2 divisors, whose sum is σ = 11141211042134. Its totient is φ = 11141211042132.

The previous prime is 11141211042131. The next prime is 11141211042209. The reversal of 11141211042133 is 33124011214111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9917315777329 + 1223895264804 = 3149177^2 + 1106298^2 .

It is a cyclic number.

It is not a de Polignac number, because 11141211042133 - 2¹ = 11141211042131 is a prime.

Together with 11141211042131, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 11141211042098 and 11141211042107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11141211042131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5570605521066 + 5570605521067.

It is an arithmetic number, because the mean of its divisors is an integer number (5570605521067).

Almost surely, 2^{11141211042133} is an apocalyptic number.

It is an amenable number.

11141211042133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11141211042133 is an equidigital number, since it uses as much as digits as its factorization.

11141211042133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 11141211042133 its reverse (33124011214111), we get a palindrome (44265222256244).

The spelling of 11141211042133 in words is "eleven trillion, one hundred forty-one billion, two hundred eleven million, forty-two thousand, one hundred thirty-three".