Base | Representation |
---|---|
bin | 10000001101110100000… |
… | …101110110100110111101 |
3 | 10221112022120020200220112 |
4 | 100031310011312212331 |
5 | 121224134110033432 |
6 | 2211531143555405 |
7 | 143336326411121 |
oct | 20156405664675 |
9 | 3845276220815 |
10 | 1114344221117 |
11 | 39a655297696 |
12 | 15bb7375bb65 |
13 | 8110b7c8b8a |
14 | 3bd12585581 |
15 | 1debee2a7b2 |
hex | 103741769bd |
1114344221117 has 2 divisors, whose sum is σ = 1114344221118. Its totient is φ = 1114344221116.
The previous prime is 1114344221077. The next prime is 1114344221119. The reversal of 1114344221117 is 7111224434111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 825782943076 + 288561278041 = 908726^2 + 537179^2 .
It is a cyclic number.
It is not a de Polignac number, because 1114344221117 - 226 = 1114277112253 is a prime.
Together with 1114344221119, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1114344221119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557172110558 + 557172110559.
It is an arithmetic number, because the mean of its divisors is an integer number (557172110559).
Almost surely, 21114344221117 is an apocalyptic number.
It is an amenable number.
1114344221117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1114344221117 is an equidigital number, since it uses as much as digits as its factorization.
1114344221117 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5376, while the sum is 32.
Adding to 1114344221117 its reverse (7111224434111), we get a palindrome (8225568655228).
The spelling of 1114344221117 in words is "one trillion, one hundred fourteen billion, three hundred forty-four million, two hundred twenty-one thousand, one hundred seventeen".
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