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1114433000 = 23539711489
BaseRepresentation
bin100001001101100…
…1110010111101000
32212200000001200022
41002123032113220
54240243324000
6302330100012
736421344542
oct10233162750
92780001608
101114433000
1152208300a
1227127a608
13149b65215
14a8018692
1567c87585
hex426ce5e8

1114433000 has 64 divisors (see below), whose sum is σ = 2634886800. Its totient is φ = 441139200.

The previous prime is 1114432997. The next prime is 1114433017. The reversal of 1114433000 is 3344111.

It can be written as a sum of positive squares in 8 ways, for example, as 75076 + 1114357924 = 274^2 + 33382^2 .

It is a super-2 number, since 2×11144330002 = 2483921822978000000, which contains 22 as substring.

It is a zygodrome in base 10.

It is a self number, because there is not a number n which added to its sum of digits gives 1114433000.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 91256 + ... + 102744.

Almost surely, 21114433000 is an apocalyptic number.

1114433000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1114433000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1317443400).

1114433000 is an abundant number, since it is smaller than the sum of its proper divisors (1520453800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1114433000 is a wasteful number, since it uses less digits than its factorization.

1114433000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11607 (or 11593 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 1114433000 is about 33383.1244792934. The cubic root of 1114433000 is about 1036.7753298258.

Adding to 1114433000 its reverse (3344111), we get a palindrome (1117777111).

Subtracting from 1114433000 its reverse (3344111), we obtain a square (1111088889 = 333332).

It can be divided in two parts, 11144 and 33000, that added together give a palindrome (44144).

The spelling of 1114433000 in words is "one billion, one hundred fourteen million, four hundred thirty-three thousand".

Divisors: 1 2 4 5 8 10 20 25 40 50 97 100 125 194 200 250 388 485 500 776 970 1000 1940 2425 3880 4850 9700 11489 12125 19400 22978 24250 45956 48500 57445 91912 97000 114890 229780 287225 459560 574450 1114433 1148900 1436125 2228866 2297800 2872250 4457732 5572165 5744500 8915464 11144330 11489000 22288660 27860825 44577320 55721650 111443300 139304125 222886600 278608250 557216500 1114433000