Base | Representation |
---|---|
bin | 10000001110110100101… |
… | …101010101110101010010 |
3 | 10221122010010011100101110 |
4 | 100032310231111311102 |
5 | 121233344122030300 |
6 | 2212230511514150 |
7 | 143405232144102 |
oct | 20166455256522 |
9 | 3848103140343 |
10 | 1115428314450 |
11 | 3a0061227a9a |
12 | 160216828956 |
13 | 8125229a618 |
14 | 3bdb6543202 |
15 | 1e0351bd550 |
hex | 103b4b55d52 |
1115428314450 has 48 divisors (see below), whose sum is σ = 2805223686336. Its totient is φ = 293258145600.
The previous prime is 1115428314439. The next prime is 1115428314457. The reversal of 1115428314450 is 544138245111.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1115428314399 and 1115428314408.
It is not an unprimeable number, because it can be changed into a prime (1115428314457) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 52356877 + ... + 52378176.
It is an arithmetic number, because the mean of its divisors is an integer number (58442160132).
Almost surely, 21115428314450 is an apocalyptic number.
1115428314450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1115428314450 is an abundant number, since it is smaller than the sum of its proper divisors (1689795371886).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1115428314450 is a wasteful number, since it uses less digits than its factorization.
1115428314450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 104735139 (or 104735134 counting only the distinct ones).
The product of its (nonzero) digits is 76800, while the sum is 39.
The spelling of 1115428314450 in words is "one trillion, one hundred fifteen billion, four hundred twenty-eight million, three hundred fourteen thousand, four hundred fifty".
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