Base | Representation |
---|---|
bin | 10000010010101111101… |
… | …000100111010111110110 |
3 | 10222000222111201111102010 |
4 | 100102233220213113312 |
5 | 121321004332004130 |
6 | 2214204335225050 |
7 | 143614451206656 |
oct | 20225750472766 |
9 | 3860874644363 |
10 | 1119638156790 |
11 | 3a192160693a |
12 | 160bb0678186 |
13 | 817735111aa |
14 | 3c2956bc366 |
15 | 1e1cea940b0 |
hex | 104afa275f6 |
1119638156790 has 32 divisors (see below), whose sum is σ = 2687576679936. Its totient is φ = 298520719200.
The previous prime is 1119638156759. The next prime is 1119638156831. The reversal of 1119638156790 is 976518369111.
It is a Smith number, since the sum of its digits (57) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a self number, because there is not a number n which added to its sum of digits gives 1119638156790.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2906686 + ... + 3269265.
It is an arithmetic number, because the mean of its divisors is an integer number (83986771248).
Almost surely, 21119638156790 is an apocalyptic number.
1119638156790 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1119638156790 is an abundant number, since it is smaller than the sum of its proper divisors (1567938523146).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1119638156790 is a wasteful number, since it uses less digits than its factorization.
1119638156790 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6182004.
The product of its (nonzero) digits is 2449440, while the sum is 57.
The spelling of 1119638156790 in words is "one trillion, one hundred nineteen billion, six hundred thirty-eight million, one hundred fifty-six thousand, seven hundred ninety".
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