Search a number
-
+
11200222201120 = 255101693083057
BaseRepresentation
bin1010001011111100000101…
…0001000000010100100000
31110122201201202001100102221
42202333001101000110200
52432001023340413440
635453151104120424
72234121642622111
oct242770121002440
943581652040387
1011200222201120
113628a954970a7
12130a817906114
1363323a7a1784
142aa144d78208
151465243c0d4a
hexa2fc1440520

11200222201120 has 48 divisors (see below), whose sum is σ = 26722510384248. Its totient is φ = 4435731558400.

The previous prime is 11200222201093. The next prime is 11200222201163. The reversal of 11200222201120 is 2110222200211.

It is a happy number.

It can be written as a sum of positive squares in 4 ways, for example, as 11199222882576 + 999318544 = 3346524^2 + 31612^2 .

It is a super-3 number, since 3×112002222011203 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is a junction number, because it is equal to n+sod(n) for n = 11200222201094 and 11200222201103.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 346525369 + ... + 346557688.

Almost surely, 211200222201120 is an apocalyptic number.

11200222201120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11200222201120 is an abundant number, since it is smaller than the sum of its proper divisors (15522288183128).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11200222201120 is a wasteful number, since it uses less digits than its factorization.

11200222201120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 693083173 (or 693083165 counting only the distinct ones).

The product of its (nonzero) digits is 64, while the sum is 16.

Adding to 11200222201120 its reverse (2110222200211), we get a palindrome (13310444401331).

Subtracting from 11200222201120 its reverse (2110222200211), we obtain a palindrome (9090000000909).

The spelling of 11200222201120 in words is "eleven trillion, two hundred billion, two hundred twenty-two million, two hundred one thousand, one hundred twenty".

Divisors: 1 2 4 5 8 10 16 20 32 40 80 101 160 202 404 505 808 1010 1616 2020 3232 4040 8080 16160 693083057 1386166114 2772332228 3465415285 5544664456 6930830570 11089328912 13861661140 22178657824 27723322280 55446644560 70001388757 110893289120 140002777514 280005555028 350006943785 560011110056 700013887570 1120022220112 1400027775140 2240044440224 2800055550280 5600111100560 11200222201120