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112013100322181 is a prime number
BaseRepresentation
bin11001011110000000010101…
…000011100000110110000101
3112200121100101112221221200222
4121132000111003200312011
5104140210312140302211
61034122035150114125
732410452022106012
oct3136002503406605
9480540345857628
10112013100322181
1132766541a57a23
1210690a807ab945
134a66a36931856
141d9366a5d2709
15ce3ab785c1db
hex65e0150e0d85

112013100322181 has 2 divisors, whose sum is σ = 112013100322182. Its totient is φ = 112013100322180.

The previous prime is 112013100322177. The next prime is 112013100322183. The reversal of 112013100322181 is 181223001310211.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 92749419422500 + 19263680899681 = 9630650^2 + 4389041^2 .

It is a cyclic number.

It is not a de Polignac number, because 112013100322181 - 22 = 112013100322177 is a prime.

It is a super-2 number, since 2×1120131003221812 (a number of 29 digits) contains 22 as substring.

Together with 112013100322183, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 112013100322181.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112013100322183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56006550161090 + 56006550161091.

It is an arithmetic number, because the mean of its divisors is an integer number (56006550161091).

Almost surely, 2112013100322181 is an apocalyptic number.

It is an amenable number.

112013100322181 is a deficient number, since it is larger than the sum of its proper divisors (1).

112013100322181 is an equidigital number, since it uses as much as digits as its factorization.

112013100322181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 26.

Adding to 112013100322181 its reverse (181223001310211), we get a palindrome (293236101632392).

The spelling of 112013100322181 in words is "one hundred twelve trillion, thirteen billion, one hundred million, three hundred twenty-two thousand, one hundred eighty-one".