11203013100230 has 48 divisors (see below), whose sum is σ = 23443432987680. Its totient is φ = 3775930725504.

The previous prime is 11203013100221. The next prime is 11203013100271. The reversal of 11203013100230 is 3200131030211.

It is a super-4 number, since 4×11203013100230⁴ (a number of 53 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11203013100199 and 11203013100208.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 22744415 + ... + 23231754.

It is an arithmetic number, because the mean of its divisors is an integer number (488404853910).

Almost surely, 2^{11203013100230} is an apocalyptic number.

11203013100230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11203013100230 is an abundant number, since it is smaller than the sum of its proper divisors (12240419887450).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11203013100230 is an equidigital number, since it uses as much as digits as its factorization.

11203013100230 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45976301 (or 45976242 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 11203013100230 its reverse (3200131030211), we get a palindrome (14403144130441).

The spelling of 11203013100230 in words is "eleven trillion, two hundred three billion, thirteen million, one hundred thousand, two hundred thirty".