Base | Representation |
---|---|
bin | 10100110111100010… |
… | …10001100101010011 |
3 | 1001220210000122001020 |
4 | 22123301101211103 |
5 | 140421022221042 |
6 | 5051410010523 |
7 | 544425435645 |
oct | 123361214523 |
9 | 31823018036 |
10 | 11203320147 |
11 | 4829a89278 |
12 | 2207b76a43 |
13 | 10970a4c26 |
14 | 783cb8895 |
15 | 4588523ec |
hex | 29bc51953 |
11203320147 has 32 divisors (see below), whose sum is σ = 15787588608. Its totient is φ = 7059177216.
The previous prime is 11203320143. The next prime is 11203320157. The reversal of 11203320147 is 74102330211.
It is a happy number.
11203320147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11203320147 - 22 = 11203320143 is a prime.
It is a super-2 number, since 2×112033201472 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (11203320143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 487878 + ... + 510324.
It is an arithmetic number, because the mean of its divisors is an integer number (493362144).
Almost surely, 211203320147 is an apocalyptic number.
11203320147 is a deficient number, since it is larger than the sum of its proper divisors (4584268461).
11203320147 is a wasteful number, since it uses less digits than its factorization.
11203320147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22619.
The product of its (nonzero) digits is 1008, while the sum is 24.
Adding to 11203320147 its reverse (74102330211), we get a palindrome (85305650358).
The spelling of 11203320147 in words is "eleven billion, two hundred three million, three hundred twenty thousand, one hundred forty-seven".
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