Base | Representation |
---|---|
bin | 11001011111010011001000… |
… | …101111001100101000110111 |
3 | 112200220211220010012000222210 |
4 | 121133103020233030220313 |
5 | 104143134411121210320 |
6 | 1034230542052024503 |
7 | 32420050263001056 |
oct | 3137231057145067 |
9 | 480824803160883 |
10 | 112102014241335 |
11 | 327a0219600438 |
12 | 106a6155902133 |
13 | 4a72236737831 |
14 | 1d97aa317639d |
15 | ce606d6a20e0 |
hex | 65f4c8bcca37 |
112102014241335 has 32 divisors (see below), whose sum is σ = 185150630154240. Its totient is φ = 57858636326400.
The previous prime is 112102014241303. The next prime is 112102014241411. The reversal of 112102014241335 is 533142410201211.
It is not a de Polignac number, because 112102014241335 - 25 = 112102014241303 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 60807046 + ... + 62623484.
It is an arithmetic number, because the mean of its divisors is an integer number (5785957192320).
Almost surely, 2112102014241335 is an apocalyptic number.
112102014241335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
112102014241335 is a deficient number, since it is larger than the sum of its proper divisors (73048615912905).
112102014241335 is a wasteful number, since it uses less digits than its factorization.
112102014241335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1949199.
The product of its (nonzero) digits is 5760, while the sum is 30.
Adding to 112102014241335 its reverse (533142410201211), we get a palindrome (645244424442546).
The spelling of 112102014241335 in words is "one hundred twelve trillion, one hundred two billion, fourteen million, two hundred forty-one thousand, three hundred thirty-five".
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