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1121121212112 = 2433112694791831
BaseRepresentation
bin10000010100001000000…
…010000001011011010000
310222011210212100111212000
4100110020002001123100
5121332024012241422
62215011434234000
7143666300032266
oct20241002013320
93864725314760
101121121212112
113a25127732a0
12161345285900
138194b84c915
143c396650436
151e269d92cac
hex105080816d0

1121121212112 has 320 divisors, whose sum is σ = 3532916736000. Its totient is φ = 337579660800.

The previous prime is 1121121212069. The next prime is 1121121212131. The reversal of 1121121212112 is 2112121211211.

It is a happy number.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a nude number because it is divisible by every one of its digits.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 612299037 + ... + 612300867.

It is an arithmetic number, because the mean of its divisors is an integer number (11040364800).

Almost surely, 21121121212112 is an apocalyptic number.

1121121212112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1121121212112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1766458368000).

1121121212112 is an abundant number, since it is smaller than the sum of its proper divisors (2411795523888).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1121121212112 is a wasteful number, since it uses less digits than its factorization.

1121121212112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2607 (or 2595 counting only the distinct ones).

The product of its digits is 32, while the sum is 18.

Adding to 1121121212112 its reverse (2112121211211), we get a palindrome (3233242423323).

Subtracting 1121121212112 from its reverse (2112121211211), we obtain a palindrome (990999999099).

It can be divided in two parts, 11 and 21121212112, that multiplied together give a palindrome (232333333232).

The spelling of 1121121212112 in words is "one trillion, one hundred twenty-one billion, one hundred twenty-one million, two hundred twelve thousand, one hundred twelve".