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112112122102207 is a prime number
BaseRepresentation
bin11001011111011100100011…
…001101101000000110111111
3112200221210222112220120102021
4121133130203031220012333
5104143321111224232312
61034235333050341011
732420555620255153
oct3137344315500677
9480853875816367
10112112122102207
11327a4536195967
12106a80b6a2a767
134a7318788b7b6
141d98381775063
15ce6460c68c07
hex65f7233681bf

112112122102207 has 2 divisors, whose sum is σ = 112112122102208. Its totient is φ = 112112122102206.

The previous prime is 112112122102193. The next prime is 112112122102231. The reversal of 112112122102207 is 702201221211211.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 112112122102207 - 243 = 103316029079999 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112112122102247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56056061051103 + 56056061051104.

It is an arithmetic number, because the mean of its divisors is an integer number (56056061051104).

Almost surely, 2112112122102207 is an apocalyptic number.

112112122102207 is a deficient number, since it is larger than the sum of its proper divisors (1).

112112122102207 is an equidigital number, since it uses as much as digits as its factorization.

112112122102207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 448, while the sum is 25.

Adding to 112112122102207 its reverse (702201221211211), we get a palindrome (814313343313418).

The spelling of 112112122102207 in words is "one hundred twelve trillion, one hundred twelve billion, one hundred twenty-two million, one hundred two thousand, two hundred seven".