Base | Representation |
---|---|
bin | 110100001101011101… |
… | …1101101111111101111 |
3 | 101201101220110120010202 |
4 | 1220122323231333233 |
5 | 3314110434342312 |
6 | 123301354224115 |
7 | 11046314610341 |
oct | 1503273557757 |
9 | 351356416122 |
10 | 112121012207 |
11 | 4360642aa66 |
12 | 1989112503b |
13 | a75aa63b09 |
14 | 55d8b7d291 |
15 | 2db34109c2 |
hex | 1a1aeedfef |
112121012207 has 2 divisors, whose sum is σ = 112121012208. Its totient is φ = 112121012206.
The previous prime is 112121012177. The next prime is 112121012231. The reversal of 112121012207 is 702210121211.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (702210121211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 112121012207 - 228 = 111852576751 is a prime.
It is a super-2 number, since 2×1121210122072 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112121012807) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56060506103 + 56060506104.
It is an arithmetic number, because the mean of its divisors is an integer number (56060506104).
Almost surely, 2112121012207 is an apocalyptic number.
112121012207 is a deficient number, since it is larger than the sum of its proper divisors (1).
112121012207 is an equidigital number, since it uses as much as digits as its factorization.
112121012207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 20.
Adding to 112121012207 its reverse (702210121211), we get a palindrome (814331133418).
The spelling of 112121012207 in words is "one hundred twelve billion, one hundred twenty-one million, twelve thousand, two hundred seven".
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