1121233313131 has 2 divisors, whose sum is σ = 1121233313132. Its totient is φ = 1121233313130.

The previous prime is 1121233313129. The next prime is 1121233313153. The reversal of 1121233313131 is 1313133321211.

It is a weak prime.

It is an emirp because it is prime and its reverse (1313133321211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1121233313131 - 2¹ = 1121233313129 is a prime.

It is a super-2 number, since 2×1121233313131² (a number of 25 digits) contains 22 as substring.

Together with 1121233313129, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1121233313096 and 1121233313105.

It is not a weakly prime, because it can be changed into another prime (1121233313111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560616656565 + 560616656566.

It is an arithmetic number, because the mean of its divisors is an integer number (560616656566).

Almost surely, 2^{1121233313131} is an apocalyptic number.

1121233313131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121233313131 is an equidigital number, since it uses as much as digits as its factorization.

1121233313131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 972, while the sum is 25.

Adding to 1121233313131 its reverse (1313133321211), we get a palindrome (2434366634342).

The spelling of 1121233313131 in words is "one trillion, one hundred twenty-one billion, two hundred thirty-three million, three hundred thirteen thousand, one hundred thirty-one".