Search a number
-
+
112124123413 is a prime number
BaseRepresentation
bin110100001101100011…
…1100101100100010101
3101201102010022121220121
41220123013211210111
53314112233422123
6123301545031541
711046353216041
oct1503307454425
9351363277817
10112124123413
1143608165505
12198921855b1
13a75b5b2c73
1455d934d021
152db382775d
hex1a1b1e5915

112124123413 has 2 divisors, whose sum is σ = 112124123414. Its totient is φ = 112124123412.

The previous prime is 112124123411. The next prime is 112124123437. The reversal of 112124123413 is 314321421211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 81794856004 + 30329267409 = 285998^2 + 174153^2 .

It is a cyclic number.

It is not a de Polignac number, because 112124123413 - 21 = 112124123411 is a prime.

It is a super-2 number, since 2×1121241234132 (a number of 23 digits) contains 22 as substring.

Together with 112124123411, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112124123411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56062061706 + 56062061707.

It is an arithmetic number, because the mean of its divisors is an integer number (56062061707).

Almost surely, 2112124123413 is an apocalyptic number.

It is an amenable number.

112124123413 is a deficient number, since it is larger than the sum of its proper divisors (1).

112124123413 is an equidigital number, since it uses as much as digits as its factorization.

112124123413 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1152, while the sum is 25.

Adding to 112124123413 its reverse (314321421211), we get a palindrome (426445544624).

The spelling of 112124123413 in words is "one hundred twelve billion, one hundred twenty-four million, one hundred twenty-three thousand, four hundred thirteen".