Base | Representation |
---|---|
bin | 11001011111101101001101… |
… | …011111100000010110111110 |
3 | 112201000112011021121001012000 |
4 | 121133231031133200112332 |
5 | 104144114230343120220 |
6 | 1034251452134123130 |
7 | 32422061132041452 |
oct | 3137551537402676 |
9 | 481015137531160 |
10 | 112130011301310 |
11 | 32801086179a32 |
12 | 106ab669ab04a6 |
13 | 4a74a78b66302 |
14 | 1d9919b59c662 |
15 | ce6b5b537390 |
hex | 65fb4d7e05be |
112130011301310 has 32 divisors (see below), whose sum is σ = 299013363470880. Its totient is φ = 29901336346944.
The previous prime is 112130011301303. The next prime is 112130011301353. The reversal of 112130011301310 is 13103110031211.
112130011301310 is a `hidden beast` number, since 1 + 1 + 21 + 30 + 0 + 1 + 1 + 301 + 310 = 666.
It is a super-2 number, since 2×1121300113013102 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 207648168807 + ... + 207648169346.
It is an arithmetic number, because the mean of its divisors is an integer number (9344167608465).
Almost surely, 2112130011301310 is an apocalyptic number.
112130011301310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
112130011301310 is an abundant number, since it is smaller than the sum of its proper divisors (186883352169570).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112130011301310 is a wasteful number, since it uses less digits than its factorization.
112130011301310 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 415296338169 (or 415296338163 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 18.
Adding to 112130011301310 its reverse (13103110031211), we get a palindrome (125233121332521).
The spelling of 112130011301310 in words is "one hundred twelve trillion, one hundred thirty billion, eleven million, three hundred one thousand, three hundred ten".
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