Base | Representation |
---|---|
bin | 110100001101101111… |
… | …0001010000100101110 |
3 | 101201102112110020002112 |
4 | 1220123132022010232 |
5 | 3314120242240420 |
6 | 123302315524022 |
7 | 11046454420634 |
oct | 1503336120456 |
9 | 351375406075 |
10 | 112130040110 |
11 | 43610536840 |
12 | 19894159612 |
13 | a75c8a507a |
14 | 55da04d354 |
15 | 2db40e58c5 |
hex | 1a1b78a12e |
112130040110 has 32 divisors (see below), whose sum is σ = 220197723264. Its totient is φ = 40771764000.
The previous prime is 112130040067. The next prime is 112130040149. The reversal of 112130040110 is 11040031211.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2255825 + ... + 2304995.
It is an arithmetic number, because the mean of its divisors is an integer number (6881178852).
Almost surely, 2112130040110 is an apocalyptic number.
112130040110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
112130040110 is a deficient number, since it is larger than the sum of its proper divisors (108067683154).
112130040110 is a wasteful number, since it uses less digits than its factorization.
112130040110 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 69920.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 112130040110 its reverse (11040031211), we get a palindrome (123170071321).
The spelling of 112130040110 in words is "one hundred twelve billion, one hundred thirty million, forty thousand, one hundred ten".
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