Base | Representation |
---|---|
bin | 11001011111101110001001… |
… | …001101011111100010000101 |
3 | 112201000121202002212101200012 |
4 | 121133232021031133202011 |
5 | 104144123303340243133 |
6 | 1034252135404400005 |
7 | 32422125016121645 |
oct | 3137561115374205 |
9 | 481017662771605 |
10 | 112131013212293 |
11 | 3280154a788539 |
12 | 106ab8a9546005 |
13 | 4a74ba85c224a |
14 | 1d99254686525 |
15 | ce6bb9494b48 |
hex | 65fb8935f885 |
112131013212293 has 2 divisors, whose sum is σ = 112131013212294. Its totient is φ = 112131013212292.
The previous prime is 112131013212269. The next prime is 112131013212347. The reversal of 112131013212293 is 392212310131211.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 59636959915009 + 52494053297284 = 7722497^2 + 7245278^2 .
It is a cyclic number.
It is not a de Polignac number, because 112131013212293 - 28 = 112131013212037 is a prime.
It is a super-4 number, since 4×1121310132122934 (a number of 57 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112131013202293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56065506606146 + 56065506606147.
It is an arithmetic number, because the mean of its divisors is an integer number (56065506606147).
Almost surely, 2112131013212293 is an apocalyptic number.
It is an amenable number.
112131013212293 is a deficient number, since it is larger than the sum of its proper divisors (1).
112131013212293 is an equidigital number, since it uses as much as digits as its factorization.
112131013212293 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 32.
The spelling of 112131013212293 in words is "one hundred twelve trillion, one hundred thirty-one billion, thirteen million, two hundred twelve thousand, two hundred ninety-three".
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