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112139812611553 is a prime number
BaseRepresentation
bin11001011111110110010101…
…101100100010010111100001
3112201001110110100111012012111
4121133312111230202113201
5104144244314012032203
61034300152502155321
732422556044564126
oct3137662554422741
9481043410435174
10112139812611553
1132805255816431
12106b1544422b41
134a7597b63797c
141d9984b1a074d
15ce7031c4926d
hex65fd95b225e1

112139812611553 has 2 divisors, whose sum is σ = 112139812611554. Its totient is φ = 112139812611552.

The previous prime is 112139812611521. The next prime is 112139812611623. The reversal of 112139812611553 is 355116218931211.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 74698544980224 + 37441267631329 = 8642832^2 + 6118927^2 .

It is a cyclic number.

It is not a de Polignac number, because 112139812611553 - 25 = 112139812611521 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112139812611497 and 112139812611506.

It is not a weakly prime, because it can be changed into another prime (112139810611553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56069906305776 + 56069906305777.

It is an arithmetic number, because the mean of its divisors is an integer number (56069906305777).

Almost surely, 2112139812611553 is an apocalyptic number.

It is an amenable number.

112139812611553 is a deficient number, since it is larger than the sum of its proper divisors (1).

112139812611553 is an equidigital number, since it uses as much as digits as its factorization.

112139812611553 is an evil number, because the sum of its binary digits is even.

The product of its digits is 388800, while the sum is 49.

The spelling of 112139812611553 in words is "one hundred twelve trillion, one hundred thirty-nine billion, eight hundred twelve million, six hundred eleven thousand, five hundred fifty-three".