Base | Representation |
---|---|
bin | 11001011111110110010101… |
… | …101100100010011000100111 |
3 | 112201001110110100111012022002 |
4 | 121133312111230202120213 |
5 | 104144244314012032443 |
6 | 1034300152502155515 |
7 | 32422556044564256 |
oct | 3137662554423047 |
9 | 481043410435262 |
10 | 112139812611623 |
11 | 32805255816495 |
12 | 106b1544422b9b |
13 | 4a7597b637a04 |
14 | 1d9984b1a079d |
15 | ce7031c492b8 |
hex | 65fd95b22627 |
112139812611623 has 2 divisors, whose sum is σ = 112139812611624. Its totient is φ = 112139812611622.
The previous prime is 112139812611553. The next prime is 112139812611641. The reversal of 112139812611623 is 326116218931211.
It is a strong prime.
It is an emirp because it is prime and its reverse (326116218931211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 112139812611623 - 216 = 112139812546087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112139812611683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56069906305811 + 56069906305812.
It is an arithmetic number, because the mean of its divisors is an integer number (56069906305812).
Almost surely, 2112139812611623 is an apocalyptic number.
112139812611623 is a deficient number, since it is larger than the sum of its proper divisors (1).
112139812611623 is an equidigital number, since it uses as much as digits as its factorization.
112139812611623 is an evil number, because the sum of its binary digits is even.
The product of its digits is 186624, while the sum is 47.
The spelling of 112139812611623 in words is "one hundred twelve trillion, one hundred thirty-nine billion, eight hundred twelve million, six hundred eleven thousand, six hundred twenty-three".
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