Base | Representation |
---|---|
bin | 10000010100011010000… |
… | …010001011100010110011 |
3 | 10222012120220200021221121 |
4 | 100110122002023202303 |
5 | 121333133322242233 |
6 | 2215101424003111 |
7 | 144006625202146 |
oct | 20243202134263 |
9 | 3865526607847 |
10 | 1121423243443 |
11 | 3a2658204968 |
12 | 16140a460497 |
13 | 819992ac199 |
14 | 3c3c47d205d |
15 | 1e28665392d |
hex | 1051a08b8b3 |
1121423243443 has 2 divisors, whose sum is σ = 1121423243444. Its totient is φ = 1121423243442.
The previous prime is 1121423243441. The next prime is 1121423243477. The reversal of 1121423243443 is 3443423241211.
It is an a-pointer prime, because the next prime (1121423243477) can be obtained adding 1121423243443 to its sum of digits (34).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1121423243443 - 21 = 1121423243441 is a prime.
Together with 1121423243441, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 1121423243399 and 1121423243408.
It is not a weakly prime, because it can be changed into another prime (1121423243441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560711621721 + 560711621722.
It is an arithmetic number, because the mean of its divisors is an integer number (560711621722).
Almost surely, 21121423243443 is an apocalyptic number.
1121423243443 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121423243443 is an equidigital number, since it uses as much as digits as its factorization.
1121423243443 is an evil number, because the sum of its binary digits is even.
The product of its digits is 55296, while the sum is 34.
Adding to 1121423243443 its reverse (3443423241211), we get a palindrome (4564846484654).
The spelling of 1121423243443 in words is "one trillion, one hundred twenty-one billion, four hundred twenty-three million, two hundred forty-three thousand, four hundred forty-three".
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