Base | Representation |
---|---|
bin | 110100010000001001… |
… | …1110011111010111100 |
3 | 101201122012012021202100 |
4 | 1220200103303322330 |
5 | 3314302032322022 |
6 | 123314335425100 |
7 | 11051461403352 |
oct | 1504023637274 |
9 | 351565167670 |
10 | 112211214012 |
11 | 43652339a07 |
12 | 198b7385190 |
13 | a773656871 |
14 | 5606b3d7d2 |
15 | 2dbb2cc1ac |
hex | 1a204f3ebc |
112211214012 has 36 divisors (see below), whose sum is σ = 283739490216. Its totient is φ = 37391279520.
The previous prime is 112211214007. The next prime is 112211214023. The reversal of 112211214012 is 210412112211.
112211214012 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a tau number, because it is divible by the number of its divisors (36).
It is a super-2 number, since 2×1122112140122 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 409203 + ... + 625994.
It is an arithmetic number, because the mean of its divisors is an integer number (7881652506).
Almost surely, 2112211214012 is an apocalyptic number.
112211214012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
112211214012 is an abundant number, since it is smaller than the sum of its proper divisors (171528276204).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112211214012 is a wasteful number, since it uses less digits than its factorization.
112211214012 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1038218 (or 1038213 counting only the distinct ones).
The product of its (nonzero) digits is 64, while the sum is 18.
Adding to 112211214012 its reverse (210412112211), we get a palindrome (322623326223).
The spelling of 112211214012 in words is "one hundred twelve billion, two hundred eleven million, two hundred fourteen thousand, twelve".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •