Base | Representation |
---|---|
bin | 110100010001000011… |
… | …1100000011111100111 |
3 | 101201201022021011111111 |
4 | 1220202013200133213 |
5 | 3314332313340033 |
6 | 123321341445451 |
7 | 11052310242442 |
oct | 1504207403747 |
9 | 351638234444 |
10 | 112241543143 |
11 | 43668474704 |
12 | 19905570887 |
13 | a779a155b2 |
14 | 560ab96659 |
15 | 2dbdcbd7cd |
hex | 1a221e07e7 |
112241543143 has 2 divisors, whose sum is σ = 112241543144. Its totient is φ = 112241543142.
The previous prime is 112241543137. The next prime is 112241543149. The reversal of 112241543143 is 341345142211.
It is a happy number.
It is a balanced prime because it is at equal distance from previous prime (112241543137) and next prime (112241543149).
It is an emirp because it is prime and its reverse (341345142211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 112241543143 - 25 = 112241543111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112241543149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56120771571 + 56120771572.
It is an arithmetic number, because the mean of its divisors is an integer number (56120771572).
Almost surely, 2112241543143 is an apocalyptic number.
112241543143 is a deficient number, since it is larger than the sum of its proper divisors (1).
112241543143 is an equidigital number, since it uses as much as digits as its factorization.
112241543143 is an evil number, because the sum of its binary digits is even.
The product of its digits is 11520, while the sum is 31.
Adding to 112241543143 its reverse (341345142211), we get a palindrome (453586685354).
The spelling of 112241543143 in words is "one hundred twelve billion, two hundred forty-one million, five hundred forty-three thousand, one hundred forty-three".
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