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11224443141047 is a prime number
BaseRepresentation
bin1010001101010110010011…
…1100100011101110110111
31110202001020202000120202002
42203111210330203232313
52432400124421003142
635512234335005515
72235640110332243
oct243254474435667
943661222016662
1011224443141047
113638294594824
12131345736989b
136355ca7a72a6
142ab3a1a87423
15146e909a5a32
hexa3564f23bb7

11224443141047 has 2 divisors, whose sum is σ = 11224443141048. Its totient is φ = 11224443141046.

The previous prime is 11224443141001. The next prime is 11224443141049. The reversal of 11224443141047 is 74014134442211.

It is a strong prime.

It is an emirp because it is prime and its reverse (74014134442211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11224443141047 - 210 = 11224443140023 is a prime.

Together with 11224443141049, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11224443141047.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11224443141049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5612221570523 + 5612221570524.

It is an arithmetic number, because the mean of its divisors is an integer number (5612221570524).

Almost surely, 211224443141047 is an apocalyptic number.

11224443141047 is a deficient number, since it is larger than the sum of its proper divisors (1).

11224443141047 is an equidigital number, since it uses as much as digits as its factorization.

11224443141047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86016, while the sum is 38.

Adding to 11224443141047 its reverse (74014134442211), we get a palindrome (85238577583258).

The spelling of 11224443141047 in words is "eleven trillion, two hundred twenty-four billion, four hundred forty-three million, one hundred forty-one thousand, forty-seven".