Base | Representation |
---|---|
bin | 1010001101011001101001… |
… | …1110110100011110111010 |
3 | 1110202010120100002112210010 |
4 | 2203112122132310132322 |
5 | 2432403444334040002 |
6 | 35512503422002350 |
7 | 2236001264564223 |
oct | 243263236643672 |
9 | 43663510075703 |
10 | 11225341315002 |
11 | 363870558a151 |
12 | 13136681163b6 |
13 | 6357118b1779 |
14 | 2ab44908a24a |
15 | 146ee477146c |
hex | a359a7b47ba |
11225341315002 has 16 divisors (see below), whose sum is σ = 22734868487040. Its totient is φ = 3694416128832.
The previous prime is 11225341314961. The next prime is 11225341315003. The reversal of 11225341315002 is 20051314352211.
It is a happy number.
It is a super-3 number, since 3×112253413150023 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (11225341315003) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11841076863 + ... + 11841077810.
It is an arithmetic number, because the mean of its divisors is an integer number (1420929280440).
Almost surely, 211225341315002 is an apocalyptic number.
11225341315002 is an abundant number, since it is smaller than the sum of its proper divisors (11509527172038).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11225341315002 is a wasteful number, since it uses less digits than its factorization.
11225341315002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23682154757.
The product of its (nonzero) digits is 7200, while the sum is 30.
Adding to 11225341315002 its reverse (20051314352211), we get a palindrome (31276655667213).
The spelling of 11225341315002 in words is "eleven trillion, two hundred twenty-five billion, three hundred forty-one million, three hundred fifteen thousand, two".
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