11225341315007 has 2 divisors, whose sum is σ = 11225341315008. Its totient is φ = 11225341315006.

The previous prime is 11225341315003. The next prime is 11225341315009. The reversal of 11225341315007 is 70051314352211.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11225341315007 - 2² = 11225341315003 is a prime.

Together with 11225341315009, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11225341315003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5612670657503 + 5612670657504.

It is an arithmetic number, because the mean of its divisors is an integer number (5612670657504).

Almost surely, 2^{11225341315007} is an apocalyptic number.

11225341315007 is a deficient number, since it is larger than the sum of its proper divisors (1).

11225341315007 is an equidigital number, since it uses as much as digits as its factorization.

11225341315007 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25200, while the sum is 35.

Adding to 11225341315007 its reverse (70051314352211), we get a palindrome (81276655667218).

The spelling of 11225341315007 in words is "eleven trillion, two hundred twenty-five billion, three hundred forty-one million, three hundred fifteen thousand, seven".