Base | Representation |
---|---|
bin | 11001100010010110101100… |
… | …111111011011000001010000 |
3 | 112201122220220112110000222121 |
4 | 121202112230333123001100 |
5 | 104210104440021130000 |
6 | 1034511231013144024 |
7 | 32441163053415031 |
oct | 3142265477330120 |
9 | 481586815400877 |
10 | 112312002130000 |
11 | 32871286264182 |
12 | 1071a99a32b014 |
13 | 4a88c900935aa |
14 | 1da3d03946a88 |
15 | ceb75d8e0b1a |
hex | 6625acfdb050 |
112312002130000 has 100 divisors (see below), whose sum is σ = 271932384632128. Its totient is φ = 44922521520000.
The previous prime is 112312002129953. The next prime is 112312002130049. The reversal of 112312002130000 is 31200213211.
It is a tau number, because it is divible by the number of its divisors (100).
It is a super-2 number, since 2×1123120021300002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (16).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 204155305 + ... + 204704695.
Almost surely, 2112312002130000 is an apocalyptic number.
112312002130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 112312002130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (135966192316064).
112312002130000 is an abundant number, since it is smaller than the sum of its proper divisors (159620382502128).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112312002130000 is an equidigital number, since it uses as much as digits as its factorization.
112312002130000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 569862 (or 569841 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 112312002130000 its reverse (31200213211), we get a palindrome (112343202343211).
The spelling of 112312002130000 in words is "one hundred twelve trillion, three hundred twelve billion, two million, one hundred thirty thousand".
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