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11231301120 = 293513236773
BaseRepresentation
bin10100111010111000…
…00000111000000000
31001222201200012201120
422131130000320000
5141000203113440
65054245432240
7545215325064
oct123534007000
931881605646
1011231301120
11484385a846
12221540b680
13109cb20c10
147878bdaa4
1545b02cdd0
hex29d700e00

11231301120 has 640 divisors, whose sum is σ = 41511343104. Its totient is φ = 2569273344.

The previous prime is 11231301079. The next prime is 11231301127. The reversal of 11231301120 is 2110313211.

It is a happy number.

It is a tau number, because it is divible by the number of its divisors (640).

It is a super-2 number, since 2×112313011202 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 11231301120.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11231301127) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 153853404 + ... + 153853476.

Almost surely, 211231301120 is an apocalyptic number.

11231301120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11231301120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20755671552).

11231301120 is an abundant number, since it is smaller than the sum of its proper divisors (30280041984).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11231301120 is a wasteful number, since it uses less digits than its factorization.

11231301120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 202 (or 186 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 11231301120 its reverse (2110313211), we get a palindrome (13341614331).

It can be divided in two parts, 1123130 and 1120, that added together give a triangular number (1124250 = T1499).

The spelling of 11231301120 in words is "eleven billion, two hundred thirty-one million, three hundred one thousand, one hundred twenty".