Base | Representation |
---|---|
bin | 1010001101110110101000… |
… | …1101001011110101111111 |
3 | 1110202212122112112202201012 |
4 | 2203131222031023311333 |
5 | 2433020413024222234 |
6 | 35520231422305435 |
7 | 2236365134542403 |
oct | 243355215136577 |
9 | 43685575482635 |
10 | 11233121320319 |
11 | 3640a38158308 |
12 | 131507972827b |
13 | 636381689702 |
14 | 2ab986449103 |
15 | 1472ec7b30ce |
hex | a376a34bd7f |
11233121320319 has 2 divisors, whose sum is σ = 11233121320320. Its totient is φ = 11233121320318.
The previous prime is 11233121320297. The next prime is 11233121320321. The reversal of 11233121320319 is 91302312133211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11233121320319 - 28 = 11233121320063 is a prime.
It is a super-2 number, since 2×112331213203192 (a number of 27 digits) contains 22 as substring.
Together with 11233121320321, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11233121620319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5616560660159 + 5616560660160.
It is an arithmetic number, because the mean of its divisors is an integer number (5616560660160).
Almost surely, 211233121320319 is an apocalyptic number.
11233121320319 is a deficient number, since it is larger than the sum of its proper divisors (1).
11233121320319 is an equidigital number, since it uses as much as digits as its factorization.
11233121320319 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5832, while the sum is 32.
The spelling of 11233121320319 in words is "eleven trillion, two hundred thirty-three billion, one hundred twenty-one million, three hundred twenty thousand, three hundred nineteen".
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