112341133123040 has 24 divisors (see below), whose sum is σ = 265405927003560. Its totient is φ = 44936453249152.

The previous prime is 112341133123039. The next prime is 112341133123091. The reversal of 112341133123040 is 40321331143211.

It is a junction number, because it is equal to n+sod(n) for n = 112341133122994 and 112341133123012.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 351066040850 + ... + 351066041169.

It is an arithmetic number, because the mean of its divisors is an integer number (11058580291815).

Almost surely, 2^{112341133123040} is an apocalyptic number.

112341133123040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

112341133123040 is an abundant number, since it is smaller than the sum of its proper divisors (153064793880520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

112341133123040 is an equidigital number, since it uses as much as digits as its factorization.

112341133123040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 702132082034 (or 702132082026 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 112341133123040 its reverse (40321331143211), we get a palindrome (152662464266251).

The spelling of 112341133123040 in words is "one hundred twelve trillion, three hundred forty-one billion, one hundred thirty-three million, one hundred twenty-three thousand, forty".