1123434330413 has 2 divisors, whose sum is σ = 1123434330414. Its totient is φ = 1123434330412.

The previous prime is 1123434330287. The next prime is 1123434330463. The reversal of 1123434330413 is 3140334343211.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1008311197609 + 115123132804 = 1004147^2 + 339298^2 .

It is a cyclic number.

It is not a de Polignac number, because 1123434330413 - 2¹² = 1123434326317 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1123434330413.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1123434330463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561717165206 + 561717165207.

It is an arithmetic number, because the mean of its divisors is an integer number (561717165207).

Almost surely, 2^{1123434330413} is an apocalyptic number.

It is an amenable number.

1123434330413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1123434330413 is an equidigital number, since it uses as much as digits as its factorization.

1123434330413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 32.

Adding to 1123434330413 its reverse (3140334343211), we get a palindrome (4263768673624).

The spelling of 1123434330413 in words is "one trillion, one hundred twenty-three billion, four hundred thirty-four million, three hundred thirty thousand, four hundred thirteen".