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11234403331302 = 231998547397643
BaseRepresentation
bin1010001101111011011010…
…0111101010110011100110
31110202222221212212200011110
42203132312213222303212
52433031024223100202
635521002540245450
72236441662500634
oct243366647526346
943688855780143
1011234403331302
113641535889118
121315376b40886
136365271666a8
142aba68806354
151473750ed26c
hexa37b69eace6

11234403331302 has 16 divisors (see below), whose sum is σ = 23651375434560. Its totient is φ = 3547706315112.

The previous prime is 11234403331241. The next prime is 11234403331351. The reversal of 11234403331302 is 20313330443211.

It is a self number, because there is not a number n which added to its sum of digits gives 11234403331302.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 49273698708 + ... + 49273698935.

It is an arithmetic number, because the mean of its divisors is an integer number (1478210964660).

Almost surely, 211234403331302 is an apocalyptic number.

11234403331302 is an abundant number, since it is smaller than the sum of its proper divisors (12416972103258).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11234403331302 is a wasteful number, since it uses less digits than its factorization.

11234403331302 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 98547397667.

The product of its (nonzero) digits is 15552, while the sum is 30.

Adding to 11234403331302 its reverse (20313330443211), we get a palindrome (31547733774513).

The spelling of 11234403331302 in words is "eleven trillion, two hundred thirty-four billion, four hundred three million, three hundred thirty-one thousand, three hundred two".

Divisors: 1 2 3 6 19 38 57 114 98547397643 197094795286 295642192929 591284385858 1872400555217 3744801110434 5617201665651 11234403331302