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11242320410149 is a prime number
BaseRepresentation
bin1010001110011000111010…
…0000111011011000100101
31110210202101122020221121221
42203212032200323120211
52433143233011111044
635524352314540341
72240142115530313
oct243461640733045
943722348227557
1011242320410149
11364492886a694
121316a064376b1
136371b946592a
142ac1ba0870b3
1514768a1b9484
hexa398e83b625

11242320410149 has 2 divisors, whose sum is σ = 11242320410150. Its totient is φ = 11242320410148.

The previous prime is 11242320410081. The next prime is 11242320410183. The reversal of 11242320410149 is 94101402324211.

It is an a-pointer prime, because the next prime (11242320410183) can be obtained adding 11242320410149 to its sum of digits (34).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7076610836100 + 4165709574049 = 2660190^2 + 2041007^2 .

It is an emirp because it is prime and its reverse (94101402324211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11242320410149 - 29 = 11242320409637 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11242320470149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5621160205074 + 5621160205075.

It is an arithmetic number, because the mean of its divisors is an integer number (5621160205075).

Almost surely, 211242320410149 is an apocalyptic number.

It is an amenable number.

11242320410149 is a deficient number, since it is larger than the sum of its proper divisors (1).

11242320410149 is an equidigital number, since it uses as much as digits as its factorization.

11242320410149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 34.

The spelling of 11242320410149 in words is "eleven trillion, two hundred forty-two billion, three hundred twenty million, four hundred ten thousand, one hundred forty-nine".