Base | Representation |
---|---|
bin | 101010111000… |
… | …111100101110 |
3 | 210011012220220 |
4 | 222320330232 |
5 | 10334241220 |
6 | 1040552210 |
7 | 164365221 |
oct | 52707456 |
9 | 23135826 |
10 | 11243310 |
11 | 638a2a1 |
12 | 3922666 |
13 | 2438760 |
14 | 16c95b8 |
15 | ec1540 |
hex | ab8f2e |
11243310 has 64 divisors (see below), whose sum is σ = 29417472. Its totient is φ = 2733696.
The previous prime is 11243303. The next prime is 11243311. The reversal of 11243310 is 1334211.
It is a super-2 number, since 2×112433102 = 252824039512200, which contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 11243310.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11243311) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 49417 + ... + 49643.
It is an arithmetic number, because the mean of its divisors is an integer number (459648).
Almost surely, 211243310 is an apocalyptic number.
11243310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 11243310, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14708736).
11243310 is an abundant number, since it is smaller than the sum of its proper divisors (18174162).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11243310 is a wasteful number, since it uses less digits than its factorization.
11243310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 377.
The product of its (nonzero) digits is 72, while the sum is 15.
The square root of 11243310 is about 3353.1045316244. The cubic root of 11243310 is about 224.0258128204.
Adding to 11243310 its reverse (1334211), we get a palindrome (12577521).
Subtracting from 11243310 its reverse (1334211), we obtain a palindrome (9909099).
The spelling of 11243310 in words is "eleven million, two hundred forty-three thousand, three hundred ten".
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