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112443123047 is a prime number
BaseRepresentation
bin110100010111000100…
…0011110010101100111
3101202020100120111010212
41220232020132111213
53320240414414142
6123353342210035
711060305530113
oct1505610362547
9352210514125
10112443123047
1143761236672
1219960b8391b
13a7ac703a48
14562986a743
152dd183ad82
hex1a2e21e567

112443123047 has 2 divisors, whose sum is σ = 112443123048. Its totient is φ = 112443123046.

The previous prime is 112443123041. The next prime is 112443123049. The reversal of 112443123047 is 740321344211.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 112443123047 - 212 = 112443118951 is a prime.

Together with 112443123049, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112443123041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56221561523 + 56221561524.

It is an arithmetic number, because the mean of its divisors is an integer number (56221561524).

Almost surely, 2112443123047 is an apocalyptic number.

112443123047 is a deficient number, since it is larger than the sum of its proper divisors (1).

112443123047 is an equidigital number, since it uses as much as digits as its factorization.

112443123047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16128, while the sum is 32.

Adding to 112443123047 its reverse (740321344211), we get a palindrome (852764467258).

The spelling of 112443123047 in words is "one hundred twelve billion, four hundred forty-three million, one hundred twenty-three thousand, forty-seven".