11251315260142 has 32 divisors (see below), whose sum is σ = 18250423787520. Its totient is φ = 5181946147200.

The previous prime is 11251315260113. The next prime is 11251315260151. The reversal of 11251315260142 is 24106251315211.

It is a super-3 number, since 3×11251315260142³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (34).

It is a junction number, because it is equal to n+sod(n) for n = 11251315260098 and 11251315260107.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 85073767 + ... + 85205917.

It is an arithmetic number, because the mean of its divisors is an integer number (570325743360).

Almost surely, 2^{11251315260142} is an apocalyptic number.

11251315260142 is a deficient number, since it is larger than the sum of its proper divisors (6999108527378).

11251315260142 is a wasteful number, since it uses less digits than its factorization.

11251315260142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 185496.

The product of its (nonzero) digits is 14400, while the sum is 34.

Adding to 11251315260142 its reverse (24106251315211), we get a palindrome (35357566575353).

The spelling of 11251315260142 in words is "eleven trillion, two hundred fifty-one billion, three hundred fifteen million, two hundred sixty thousand, one hundred forty-two".