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113001437 is a prime number
BaseRepresentation
bin1101011110001…
…00001111011101
321212122001211102
412233010033131
5212412021222
615114002445
72541332153
oct657041735
9255561742
10113001437
115887171a
1231a16425
131a546573
14110173d3
159dc1d92
hex6bc43dd

113001437 has 2 divisors, whose sum is σ = 113001438. Its totient is φ = 113001436.

The previous prime is 113001433. The next prime is 113001439. The reversal of 113001437 is 734100311.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 74200996 + 38800441 = 8614^2 + 6229^2 .

It is a cyclic number.

It is not a de Polignac number, because 113001437 - 22 = 113001433 is a prime.

Together with 113001439, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113001433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56500718 + 56500719.

It is an arithmetic number, because the mean of its divisors is an integer number (56500719).

Almost surely, 2113001437 is an apocalyptic number.

It is an amenable number.

113001437 is a deficient number, since it is larger than the sum of its proper divisors (1).

113001437 is an equidigital number, since it uses as much as digits as its factorization.

113001437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 20.

The square root of 113001437 is about 10630.2134033142. The cubic root of 113001437 is about 483.4608620544.

Adding to 113001437 its reverse (734100311), we get a palindrome (847101748).

The spelling of 113001437 in words is "one hundred thirteen million, one thousand, four hundred thirty-seven".