Base | Representation |
---|---|
bin | 1010010001110001011011… |
… | …0101101011001101010111 |
3 | 1111000022102020111222201211 |
4 | 2210130112311223031113 |
5 | 2440121301141001033 |
6 | 40011203525002251 |
7 | 2244300330126403 |
oct | 244342665531527 |
9 | 44008366458654 |
10 | 11300442125143 |
11 | 3667543a83396 |
12 | 1326127253387 |
13 | 63c81ca23172 |
14 | 2b0d312c6103 |
15 | 148e3ca9d2cd |
hex | a4716d6b357 |
11300442125143 has 2 divisors, whose sum is σ = 11300442125144. Its totient is φ = 11300442125142.
The previous prime is 11300442125107. The next prime is 11300442125179. The reversal of 11300442125143 is 34152124400311.
It is a happy number.
It is a balanced prime because it is at equal distance from previous prime (11300442125107) and next prime (11300442125179).
It is a cyclic number.
It is not a de Polignac number, because 11300442125143 - 221 = 11300440027991 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11300442125543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650221062571 + 5650221062572.
It is an arithmetic number, because the mean of its divisors is an integer number (5650221062572).
Almost surely, 211300442125143 is an apocalyptic number.
11300442125143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11300442125143 is an equidigital number, since it uses as much as digits as its factorization.
11300442125143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 11300442125143 its reverse (34152124400311), we get a palindrome (45452566525454).
The spelling of 11300442125143 in words is "eleven trillion, three hundred billion, four hundred forty-two million, one hundred twenty-five thousand, one hundred forty-three".
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