Base | Representation |
---|---|
bin | 1010010001110111011001… |
… | …0001011100011011001100 |
3 | 1111000110112211022001121021 |
4 | 2210131312101130123030 |
5 | 2440133041032141030 |
6 | 40012030442243524 |
7 | 2244355111312222 |
oct | 244356621343314 |
9 | 44013484261537 |
10 | 11302043240140 |
11 | 3668195846824 |
12 | 13264b34b65a4 |
13 | 63ca166595a3 |
14 | 2b1043bcab12 |
15 | 148ed341c97a |
hex | a477645c6cc |
11302043240140 has 96 divisors (see below), whose sum is σ = 25032068107200. Its totient is φ = 4274555535360.
The previous prime is 11302043240129. The next prime is 11302043240161. The reversal of 11302043240140 is 4104234020311.
11302043240140 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 434196646 + ... + 434222674.
It is an arithmetic number, because the mean of its divisors is an integer number (260750709450).
Almost surely, 211302043240140 is an apocalyptic number.
11302043240140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11302043240140 is an abundant number, since it is smaller than the sum of its proper divisors (13730024867060).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11302043240140 is a wasteful number, since it uses less digits than its factorization.
11302043240140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28235 (or 28233 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 11302043240140 its reverse (4104234020311), we get a palindrome (15406277260451).
The spelling of 11302043240140 in words is "eleven trillion, three hundred two billion, forty-three million, two hundred forty thousand, one hundred forty".
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