Base | Representation |
---|---|
bin | 110100101000010111… |
… | …0001000101110011101 |
3 | 101210201210111200202021 |
4 | 1221100232020232131 |
5 | 3322432443440331 |
6 | 123531112100141 |
7 | 11110553141635 |
oct | 1512056105635 |
9 | 353653450667 |
10 | 113023421341 |
11 | 43a29858336 |
12 | 19aa3394651 |
13 | a8729c1c0c |
14 | 56829656c5 |
15 | 2e17766211 |
hex | 1a50b88b9d |
113023421341 has 2 divisors, whose sum is σ = 113023421342. Its totient is φ = 113023421340.
The previous prime is 113023421339. The next prime is 113023421359. The reversal of 113023421341 is 143124320311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 63619468441 + 49403952900 = 252229^2 + 222270^2 .
It is a cyclic number.
It is not a de Polignac number, because 113023421341 - 21 = 113023421339 is a prime.
Together with 113023421339, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113023421041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56511710670 + 56511710671.
It is an arithmetic number, because the mean of its divisors is an integer number (56511710671).
Almost surely, 2113023421341 is an apocalyptic number.
It is an amenable number.
113023421341 is a deficient number, since it is larger than the sum of its proper divisors (1).
113023421341 is an equidigital number, since it uses as much as digits as its factorization.
113023421341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 113023421341 its reverse (143124320311), we get a palindrome (256147741652).
The spelling of 113023421341 in words is "one hundred thirteen billion, twenty-three million, four hundred twenty-one thousand, three hundred forty-one".
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