Base | Representation |
---|---|
bin | 11001101100110011101101… |
… | …010100110010111010010100 |
3 | 112211012121001210210020000121 |
4 | 121230303231110302322110 |
5 | 104303342114244410030 |
6 | 1040221231040321324 |
7 | 32544113135240125 |
oct | 3154635524627224 |
9 | 484177053706017 |
10 | 113030341013140 |
11 | 33018997897141 |
12 | 10816054613244 |
13 | 4b0b93ba23c75 |
14 | 1dca9aa69004c |
15 | d102a299147a |
hex | 66cced532e94 |
113030341013140 has 48 divisors (see below), whose sum is σ = 242417003092992. Its totient is φ = 44249629326336.
The previous prime is 113030341013123. The next prime is 113030341013141. The reversal of 113030341013140 is 41310143030311.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113030341013141) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 80048932 + ... + 81448708.
It is an arithmetic number, because the mean of its divisors is an integer number (5050354231104).
Almost surely, 2113030341013140 is an apocalyptic number.
113030341013140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113030341013140 is an abundant number, since it is smaller than the sum of its proper divisors (129386662079852).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113030341013140 is a wasteful number, since it uses less digits than its factorization.
113030341013140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1485736 (or 1485734 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 113030341013140 its reverse (41310143030311), we get a palindrome (154340484043451).
The spelling of 113030341013140 in words is "one hundred thirteen trillion, thirty billion, three hundred forty-one million, thirteen thousand, one hundred forty".
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