Base | Representation |
---|---|
bin | 10101000011100101… |
… | …11100011111110111 |
3 | 1002011211021002211212 |
4 | 22201302330133313 |
5 | 141122412440432 |
6 | 5105420552035 |
7 | 550063665461 |
oct | 124162743767 |
9 | 32154232755 |
10 | 11304421367 |
11 | 48810620a8 |
12 | 22359b261b |
13 | 10b2012a35 |
14 | 7934b5131 |
15 | 4626732b2 |
hex | 2a1cbc7f7 |
11304421367 has 2 divisors, whose sum is σ = 11304421368. Its totient is φ = 11304421366.
The previous prime is 11304421327. The next prime is 11304421379. The reversal of 11304421367 is 76312440311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11304421367 - 28 = 11304421111 is a prime.
It is a super-3 number, since 3×113044213673 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11304421327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5652210683 + 5652210684.
It is an arithmetic number, because the mean of its divisors is an integer number (5652210684).
Almost surely, 211304421367 is an apocalyptic number.
11304421367 is a deficient number, since it is larger than the sum of its proper divisors (1).
11304421367 is an equidigital number, since it uses as much as digits as its factorization.
11304421367 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 32.
Adding to 11304421367 its reverse (76312440311), we get a palindrome (87616861678).
The spelling of 11304421367 in words is "eleven billion, three hundred four million, four hundred twenty-one thousand, three hundred sixty-seven".
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