Base | Representation |
---|---|
bin | 10000011101010101100… |
… | …001110001000101111000 |
3 | 11000010100010022202011102 |
4 | 100131111201301011320 |
5 | 122012302344022130 |
6 | 2223325053350532 |
7 | 144466341355556 |
oct | 20352541610570 |
9 | 4003303282142 |
10 | 1131011314040 |
11 | 3a6728446253 |
12 | 163245498448 |
13 | 8286683c23a |
14 | 3ca53d66bd6 |
15 | 1e648293645 |
hex | 10755871178 |
1131011314040 has 64 divisors (see below), whose sum is σ = 2578174164000. Its totient is φ = 446505666048.
The previous prime is 1131011313931. The next prime is 1131011314091. The reversal of 1131011314040 is 404131101311.
It is a super-2 number, since 2×11310113140402 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 331367 + ... + 1540073.
Almost surely, 21131011314040 is an apocalyptic number.
1131011314040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1131011314040 is an abundant number, since it is smaller than the sum of its proper divisors (1447162849960).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1131011314040 is a wasteful number, since it uses less digits than its factorization.
1131011314040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1209024 (or 1209020 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 1131011314040 its reverse (404131101311), we get a palindrome (1535142415351).
The spelling of 1131011314040 in words is "one trillion, one hundred thirty-one billion, eleven million, three hundred fourteen thousand, forty".
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