11310414132 has 12 divisors (see below), whose sum is σ = 26390966336. Its totient is φ = 3770138040.

The previous prime is 11310414131. The next prime is 11310414169. The reversal of 11310414132 is 23141401311.

It is a tau number, because it is divible by the number of its divisors (12).

It is a junction number, because it is equal to n+sod(n) for n = 11310414099 and 11310414108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11310414131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 471267244 + ... + 471267267.

Almost surely, 2^11310414132 is an apocalyptic number.

11310414132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

11310414132 is an abundant number, since it is smaller than the sum of its proper divisors (15080552204).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11310414132 is a wasteful number, since it uses less digits than its factorization.

11310414132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 942534518 (or 942534516 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 11310414132 its reverse (23141401311), we get a palindrome (34451815443).

The spelling of 11310414132 in words is "eleven billion, three hundred ten million, four hundred fourteen thousand, one hundred thirty-two".