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1131103001999 is a prime number
BaseRepresentation
bin10000011101011010111…
…111100001110110001111
311000010120111211222101202
4100131122333201312033
5122012444332030444
62223342130500115
7144501533611445
oct20353277416617
94003514758352
101131103001999
113a677517a823
1216327013463b
138287c832579
143ca621d2b95
151e65135534e
hex1075afe1d8f

1131103001999 has 2 divisors, whose sum is σ = 1131103002000. Its totient is φ = 1131103001998.

The previous prime is 1131103001981. The next prime is 1131103002013. The reversal of 1131103001999 is 9991003011311.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1131103001999 is a prime.

It is a super-2 number, since 2×11311030019992 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131103001909) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565551500999 + 565551501000.

It is an arithmetic number, because the mean of its divisors is an integer number (565551501000).

Almost surely, 21131103001999 is an apocalyptic number.

1131103001999 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131103001999 is an equidigital number, since it uses as much as digits as its factorization.

1131103001999 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6561, while the sum is 38.

The spelling of 1131103001999 in words is "one trillion, one hundred thirty-one billion, one hundred three million, one thousand, nine hundred ninety-nine".